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Hy community,
My test model (see attached picture) with linear elements (3D/DKT) produces a deformation of 1.77 mm.
There is no difference between 3D and 3D-SI. The same calculation with Abaqus gives a displacement of 1.79 mm with C3D8/S4 elements. If I replace C3D8 with C3D8R (reduced integration), I obtain a displacement of 2.64 mm.
I expect a result around 2.5 mm ( beam, analytically FL³/3EI). I also obtain this with a pure shell model.
Have I missed something (3D versus 3D-SI)?
Best Regards,
Hansbau52
Last edited by Hansbau52 (2022-05-13 10:36:38)
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hello,
you should obtain a very good result wrt beam theory, if you use quadratic elements (HEXA20 instead of HEXA8). And set NU=0 (because a beam has no lateral contraction)
Moreover you must take care how to attach the DKT-elm to the 3D-elm. If you have fused (shared) nodes with an overlapping, then your model is too stiff in this region by factor 2. It is better done without overlapping with the glue contact:
AFFE_CHAR_MECA(..LIAISON_MAIL( .. TYPE_RACCORD='COQUE_MASSIF' . .
Best regards
Johannes_ACKVA
*** NEW: all Code-Aster courses now as Video and Webinar courses ***
Ingenieurbüro für Mechanik
D 91717 Wassertrüdingen / Germany
www.code-aster.de Training & Support for NASTRAN and CODE-ASTER
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Hello Dr. Ackva,
thank you very much for your answer. I had of course set the cross-contraction to zero and also used the connection with COQUE-MASSIF without overlap. My question was about the reduced integration for the linear 3D elements. In Abaqus it is standard and leads to relatively good results. With Code_aster I did not notice any difference. Can you please tell me something about this?
Best regards,
Hansbau52
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hello
your questions are answered in doc U2.01.10:
subintegration (modelisation='3D_SI' instead of '3D') meaningful when dealing with (nearly) incompressible materials,
quadratic elements (HEXA20 instead of HEXA8, TETRA10 instead of TETRA4) recommended for the mechanical analyses
Best regards
Johannes_ACKVA
*** NEW: all Code-Aster courses now as Video and Webinar courses ***
Ingenieurbüro für Mechanik
D 91717 Wassertrüdingen / Germany
www.code-aster.de Training & Support for NASTRAN and CODE-ASTER
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Hello Dr. Ackva,
of course, the square elements are preferable. I just wanted to understand with the linear elements the difference in approach Abaqus/Code_aster. As I said, in Abaqus the under-integration is set as default for linear quadrilateral elements (2D) and also for the linear hexahedra. In addition, any control parameters are still used. The intention is to get a grip on locking and hourglass effects. I think we should end the discussion with this and I thank you expressly for your hints.
Best regards,
Hansbau52
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