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Monsieurs,
J'ai rencontré un problème lors d'un étude dans lequel je voudrais réaliser un analyse de fatigue de type de Wohler en utilisant CALC_FATIGUE, et je me réfère sur l'exemple szlz105a pour l'édition du fichier .comm, mais il appaît toujous des erreurs dans les executions.
J'ai créé le maillage de la structure de tuyau comme un arête avec deux coudes( en fait c'est le maillage de l'exemple sdlx02d), et j'utilise la modélisation de TUYAU_6M, et les autres commandes sont tous similaires aux celles de szlz105a.
Voici mon fichier .comm et .med, j'utilise Salome-Meca2018 de version Windows.
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Merci de m'en débarrasser!
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Y a quelqu'un peut m'aider?
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Comment faire un analyse simple de fatigue sur tuyau?
1) draw a cylinder
2) define 3 geometrical groups : " fix "= a base of cylinder ; "load" = the other base : "c" = the volume.
3) generate mesh and groups of mesh from geometry.
4) open aster module
5) add a new stage
6) select, copy ( CTRL+C) and paste ( CTRL+V) this code in the stage :
DEBUT(LANG='EN')
tstep = 0.5
mesh = LIRE_MAILLAGE(identifier='1:1',
FORMAT='MED',
UNITE=20)
model = AFFE_MODELE(identifier='2:1',
AFFE=_F(MODELISATION=('3D', ),
PHENOMENE='MECANIQUE',
TOUT='OUI'),
MAILLAGE=mesh)
ys = DEFI_CONSTANTE(identifier='3:1',
VALE=210000000000.0)
ps = DEFI_CONSTANTE(identifier='4:1',
VALE=0.3)
ds = DEFI_CONSTANTE(identifier='5:1',
VALE=8000.0)
wholer = DEFI_FONCTION(identifier='6:1',
INTERPOL=('LIN', 'LOG'),
NOM_PARA='SIGM',
PROL_DROITE='LINEAIRE',
PROL_GAUCHE='CONSTANT',
VALE=(86200000.0, 1000000.0, 114000000.0, 200000.0, 138000000.0, 100000.0, 214000000.0, 20000.0, 262000000.0, 10000.0, 441000000.0, 2000.0, 1070000000.0, 200.0, 1410000000.0, 100.0, 1900000000.0, 50.0, 2830000000.0, 20.0, 4000000000.0, 10.0))
steel = DEFI_MATERIAU(identifier='7:1',
ECRO_LINE=_F(D_SIGM_EPSI=1100000000.0,
SY=700000000.0),
ELAS_FO=_F(E=ys,
NU=ps,
RHO=ds),
FATIGUE=_F(WOHLER=wholer),
RCCM=_F(SU=900000000.0))
fieldmat = AFFE_MATERIAU(identifier='8:1',
AFFE=_F(MATER=(steel, ),
TOUT='OUI'),
MODELE=model)
loadf = DEFI_FONCTION(identifier='9:1',
NOM_PARA='INST',
PROL_DROITE='CONSTANT',
PROL_GAUCHE='EXCLU',
VALE=(1.0, 70000000.0, 2.0, -70000000.0, 3.0, 70000000.0, 4.0, -70000000.0, 5.0, 70000000.0, 6.0, -70000000.0, 7.0, 70000000.0, 8.0, -70000000.0, 9.0, 70000000.0, 10.0, -70000000.0))
listr = DEFI_LIST_REEL(identifier='10:1',
DEBUT=1.0,
INTERVALLE=_F(JUSQU_A=10.0,
PAS=tstep))
times = DEFI_LIST_INST(identifier='11:1',
DEFI_LIST=_F(LIST_INST=listr),
METHODE='AUTO')
load = AFFE_CHAR_MECA(identifier='12:1',
FACE_IMPO=_F(DX=0.0,
DY=0.0,
DZ=0.0,
GROUP_MA=('fix', )),
MODELE=model)
loadd = AFFE_CHAR_MECA_F(identifier='13:1',
FORCE_FACE=_F(FY=loadf,
GROUP_MA=('load', )),
MODELE=model)
resnonl = DYNA_NON_LINE(identifier='14:1',
CHAM_MATER=fieldmat,
COMPORTEMENT=_F(DEFORMATION='SIMO_MIEHE',
RELATION='VMIS_ISOT_LINE'),
CONVERGENCE=_F(ITER_GLOB_MAXI=50),
EXCIT=(_F(CHARGE=load),
_F(CHARGE=loadd)),
INCREMENT=_F(LIST_INST=times),
MODELE=model,
NEWTON=_F(MATRICE='TANGENTE',
PREDICTION='TANGENTE'),
SCHEMA_TEMPS=_F(FORMULATION='DEPLACEMENT',
SCHEMA='HHT'),
SOLVEUR=_F(METHODE='MUMPS'))
resnonl = CALC_CHAMP(identifier='15:1',
reuse=resnonl,
CRITERES=('SIEQ_ELGA', ),
RESULTAT=resnonl)
fati = CALC_FATIGUE(identifier='16:1',
DOMMAGE='WOHLER',
HISTOIRE=_F(EQUI_GD='VMIS_SG',
RESULTAT=resnonl),
MATER=steel,
OPTION='DOMA_ELGA_SIGM',
TYPE_CALCUL='CUMUL_DOMMAGE')
IMPR_RESU(identifier='17:1',
FORMAT='MED',
RESU=(_F(RESULTAT=resnonl),
_F(CHAM_GD=fati,
NOM_CHAM_MED=('DOMA', ),
NOM_CMP=('DOMA', ))),
UNITE=2)
FIN()
7) in the tree pasted delete deprecated
8) reassigning the mesh
9) reassigning the directory of output results.
10 ) run.
Mechanical Engineer.
Salome_Meca User.
C u m grano salis.
Si lavora e si fatica per il pane e la φca.
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1) draw a cylinder
the procedure is the same drawing a tube (or a plate with hole)
Mechanical Engineer.
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Si lavora e si fatica per il pane e la φca.
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the procedure is the same if you use STAT_NON_LINE
Mechanical Engineer.
Salome_Meca User.
C u m grano salis.
Si lavora e si fatica per il pane e la φca.
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miib,
thank you for your explication, but this command file still won't work with my pipe model, maybe I should learn more from files of non-linear analysis..
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miib,
thank you for your explication, but this command file still won't work with my pipe model, maybe I should learn more from files of non-linear analysis..
can you show the message error of the tipe like attached file ??? :-)
Mechanical Engineer.
Salome_Meca User.
C u m grano salis.
Si lavora e si fatica per il pane e la φca.
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attachment
Mechanical Engineer.
Salome_Meca User.
C u m grano salis.
Si lavora e si fatica per il pane e la φca.
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Perceval Zhou wrote:miib,
thank you for your explication, but this command file still won't work with my pipe model, maybe I should learn more from files of non-linear analysis..can you show the message error of the tipe like attached file ??? :-)
Yes, it shows that the modelisation is not compatible with the choice "SIMO_MIEHE"
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1) draw a cylinder
2) define 3 geometrical groups : " fix "= a base of cylinder ; "load" = the other base : "c" = the volume.
3) generate mesh and groups of mesh from geometry.
the procedure is the same drawing a tube (or a plate with hole)
mesh = LIRE_MAILLAGE(identifier='1:1',
FORMAT='MED',
UNITE=20)model = AFFE_MODELE(identifier='2:1',
AFFE=_F(MODELISATION=('3D', ),
PHENOMENE='MECANIQUE',
TOUT='OUI'),
MAILLAGE=mesh)
p.s. naturally you must adapt your loads to your case study
Mechanical Engineer.
Salome_Meca User.
C u m grano salis.
Si lavora e si fatica per il pane e la φca.
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attached here an example of capability
Mechanical Engineer.
Salome_Meca User.
C u m grano salis.
Si lavora e si fatica per il pane e la φca.
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